(3x+4)(2x^2+4x-1)=

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Solution for (3x+4)(2x^2+4x-1)= equation: 


Simplifying
(3x + 4)(2x2 + 4x + -1) = 0

Reorder the terms:
(4 + 3x)(2x2 + 4x + -1) = 0

Reorder the terms:
(4 + 3x)(-1 + 4x + 2x2) = 0

Multiply (4 + 3x) * (-1 + 4x + 2x2)
(4(-1 + 4x + 2x2) + 3x * (-1 + 4x + 2x2)) = 0
((-1 * 4 + 4x * 4 + 2x2 * 4) + 3x * (-1 + 4x + 2x2)) = 0
((-4 + 16x + 8x2) + 3x * (-1 + 4x + 2x2)) = 0
(-4 + 16x + 8x2 + (-1 * 3x + 4x * 3x + 2x2 * 3x)) = 0
(-4 + 16x + 8x2 + (-3x + 12x2 + 6x3)) = 0

Reorder the terms:
(-4 + 16x + -3x + 8x2 + 12x2 + 6x3) = 0

Combine like terms: 16x + -3x = 13x
(-4 + 13x + 8x2 + 12x2 + 6x3) = 0

Combine like terms: 8x2 + 12x2 = 20x2
(-4 + 13x + 20x2 + 6x3) = 0

Solving
-4 + 13x + 20x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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